JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    In a \[0.2\] molal aqueous solution of a weak acid HX, the degree of ionisation is \[0.3\]. Taking \[{{K}_{f}}\] for water as \[1.85\], the freezing point of the solution will be nearest to     AIEEE  Solved  Paper-2003

    A)                         \[-{{0.480}^{o}}C\]       

    B)       \[-{{0.360}^{o}}C\]                         

    C) \[-{{0.260}^{o}}C\]        

    D)       \[+\,{{0.480}^{o}}C\]

    Correct Answer: A

    Solution :

    \[\Delta {{T}_{f}}=molality\,\times {{K}_{f}}\times i\]                          \[H\,X\,{{H}^{+}}+{{X}^{-1}}\] \[=0.2\times 1.85\times 1.3\]                                         \[\alpha =0.3\] \[\therefore \,\,Fp=-{{0.481}^{\text{o}}}C\]                                       \[i=1+\alpha =1.3\]


You need to login to perform this action.
You will be redirected in 3 sec spinner