JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    When during electrolysis of a solution of \[AgN{{O}_{3}}\], 9650 coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be     AIEEE  Solved  Paper-2003

    A)                         \[1.08\] g                            

    B) \[10.8\] g                            

    C) \[21.6\] g                            

    D) 108 g

    Correct Answer: B

    Solution :

    \[A{{g}^{+}}+{{e}^{-}}\xrightarrow{{}}Ag\]  9650C = 0.1 F = 0.1 equivalent Ag                                     = 0.1 mol Ag                                 = 10.8 g Ag


You need to login to perform this action.
You will be redirected in 3 sec spinner