A) \[7/5\]
B) \[2/5\]
C) \[24/16\]
D) \[12/7\]
Correct Answer: C
Solution :
Using the relation, \[\frac{{{n}_{1}}+{{n}_{2}}}{\gamma -1}=\frac{{{n}_{1}}}{{{\gamma }_{1}}-1}+\frac{{{n}_{2}}}{{{\gamma }_{2}}-1}\], we get \[\frac{1+1}{\gamma -1}=\frac{1}{(5/3-1)}+\frac{1}{(7/5-1)}\] \[\Rightarrow \frac{2}{\gamma -1}=\frac{3}{2}+\frac{5}{2}=4\] \[\Rightarrow \gamma =\frac{3}{2}=\frac{24}{16}\]
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