A) zero, since it contains \[C{{l}_{2}}\]
B) -1, since it contains \[C{{l}^{-}}\]
C) +1, since it contains \[Cl{{O}^{-}}\]
D) +1 and -1 since it contains \[Cl{{O}^{-}}\] and \[C{{l}^{-}}\]
Correct Answer: D
Solution :
\[CaOC{{l}_{2}}\] is written basically as \[Ca(OCl)Cl\] \[CC{{l}^{-}}\xrightarrow{{}}Cl\] has \[+1\] oxidation state \[C{{l}^{-}}\xrightarrow{{}}Cl\] has \[-1\] oxidation state
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