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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    If \[y={{\sin }^{2}}\theta +\cos e{{c}^{2}}\theta ,\,\,\theta \ne 0\], then   AIEEE  Solved  Paper-2002

    A) \[y=0\]    

    B)                           \[y\le 2\]                                

    C)           \[y\ge -2\]             

    D)           \[y\ge 2\]  

    Correct Answer: D

    Solution :

    Since, \[y={{\sin }^{2}}\theta +\cos e{{c}^{2}}\theta \]                                 \[={{\sin }^{2}}\theta +\cos e{{c}^{2}}\theta -2+2\]              \[={{(\sin \theta -\cos ec\theta )}^{2}}+2\]             \[\left( \cos ec\theta =\frac{1}{\sin \theta } \right)\] \[\Rightarrow \]   \[y\ge 2\]


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