A) \[2\,\,\Omega \]
B) \[6\,\,\Omega \]
C) \[5\,\,\Omega \]
D) \[4\,\,\Omega \]
Correct Answer: B
Solution :
As power \[P=\frac{{{V}^{2}}}{{{R}_{net}}}\] (as V is constant in parallel) \[\Rightarrow \] \[150=\frac{{{(15)}^{2}}}{\frac{R\times 2}{2+R}}\Rightarrow R=6\,\,\Omega \]You need to login to perform this action.
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