A) \[x=-1\]
B) \[x=1\]
C) \[x=-3/2\]
D) \[x=3/2\]
Correct Answer: D
Solution :
The equation of parabola is \[{{y}^{2}}+4y+4x+2=0\] \[\Rightarrow \] \[{{y}^{2}}+4y+4=-4x-2+4\] \[\Rightarrow \] \[{{(y-2)}^{2}}=-4\left( x-\frac{1}{2} \right)\] Let \[y+2=Y\]and \[x-\frac{1}{2}=x\] \[\therefore \] \[{{Y}^{2}}=-4x\] Here, \[a=1\] \[\therefore \] Equation of directrix is \[x=1\]. \[\Rightarrow \] \[x-\frac{1}{2}=1\Rightarrow x=\frac{3}{2}\]
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