JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    A problem in Mathematics is given to three students A, B, C and their respective probability of solving the problem is \[\frac{1}{2},\frac{1}{3}\] and \[\frac{1}{4}\]. Probability that the problem is solved, is   AIEEE  Solved  Paper-2002

    A) 3/4            

    B)           1/2                            

    C) 2/3                            

    D)           1/3

    Correct Answer: A

    Solution :

    Use the relation P(A) + P \[(\overline{A})\] = 1, where P(A) = probabilities of solved question by A and P \[(\overline{A})\] = probabilities of not solved question by B. Since, probabilities of solving the problem by A, B and C are \[\frac{1}{2},\frac{1}{3}\] and \[\frac{1}{4}\], respectively.              \[\therefore \] Probability that the problem is not solved                                 \[=P(\overline{A})P(\overline{B})(\overline{C})\]                                 \[=\left( 1-\frac{1}{2} \right)\left( 1-\frac{1}{3} \right)\left( 1-\frac{1}{4} \right)\]                                 \[=\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}=\frac{1}{4}\] Hence, the probability that the problem is solved                    \[=1-\frac{1}{4}=\frac{3}{4}\]


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