A) \[1:2\]
B) \[1:4\]
C) \[2:1\]
D) \[4:1\]
Correct Answer: C
Solution :
Let the tubes A and Shave equal length called as\[l\]. Since, tube A is opened at both the ends therefore its fundamental frequency \[{{n}_{A}}=\frac{v}{2\,l}\] ... (i) Since, tube B is closed at one end, therefore its fundamental frequency \[{{n}_{B}}=\frac{v}{4\,l}\] ?. (ii) From Eqs. (i) and (ii), we get \[\frac{{{n}_{A}}}{{{n}_{B}}}=\frac{v/2\,l}{v/4\,l}=\frac{4}{2}=2:1\]You need to login to perform this action.
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