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JEE Main & Advanced AIEEE Solved Paper-2002

  • question_answer
    If \[13.6\] eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from \[n=2\], is   AIEEE  Solved  Paper-2002

    A) \[10.2\] eV  

    B)                           0 eV                         

    C) \[3.4\] eV      

    D)           \[6.8\] eV

    Correct Answer: C

    Solution :

                       Energy required to remove an electron from nth orbit of H-atom is                                 \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}\]              Here,                        \[n=2\]              Therefore,      \[{{E}_{2}}=-\frac{13.6}{{{2}^{2}}}=-3.4\,V\]


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