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JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

  • question_answer
    Let \[f:R\to [0,\infty )\] be such that \[\underset{x\to 5}{\mathop{\lim }}\,f(x)\] exists and \[\underset{x\to 5}{\mathop{\lim }}\,\frac{{{(f(x))}^{2}}-9}{\sqrt{|x-5|}}=0\] Then \[\underset{x\to 5}{\mathop{\lim }}\,f(x)\]equals:     AIEEE  Solved  Paper (Held On 11 May  2011)

    A)  0

    B)  1

    C)  2

    D)  3

    Correct Answer: D

    Solution :

                    \[\underset{x\to 5}{\mathop{\ell \lim }}\,\frac{(f{{(x)}^{2}})-9}{\sqrt{|x-5|}}=0\] \[\underset{x\to 5}{\mathop{\ell im}}\,[f{{(f(x))}^{2}}-9]=0\] \[\underset{x\to 5}{\mathop{\ell im}}\,f(x)=3\]


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