A) \[{{x}^{2}}+{{y}^{2}}-2x-2y+1=0\]
B) \[~{{x}^{2}}+{{y}^{2}}-x-y=0\]
C) \[{{x}^{2}}+{{y}^{2}}+2x+2y-7=0\]
D) \[{{x}^{2}}+{{y}^{2}}+x+y-2=0\]
Correct Answer: B
Solution :
Circle whose diametric end points are (1,0) and (0,1) will be of smallest radius. \[(x-1)(x-0)+(y-0)(y-1)=0\] \[{{x}^{2}}+{{y}^{2}}-x-y=0\]
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