JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

  • question_answer
    Statement -1 : A nucleus having energy \[{{E}_{1}}\] decays by \[\text{ }\!\!\beta\!\!\text{ -}\]emission to daughter nucleus having energy \[{{E}_{2}},\] but the \[\text{ }\!\!\beta\!\!\text{ -}\]rays are emitted with a continuous energy spectrum having end point energy \[{{E}_{1}}-{{E}_{2}}.\] Statement - 2: To conserve energy and momentum in p-decay at least three particles must take part in the transformation.     AIEEE  Solved  Paper (Held On 11 May  2011)

    A)  Statement-1 is correct but statement-2 is not correct.

    B)  Statement-1 and Statement-2 both are correct and stateemnt-2 is the correct explanation of statement-1.

    C)  Statement-1 is correct, Statement-2 is correct and Statement-2 is not the correct explanation of Statement-1

    D)  Statement-1 is incorrect, Statement-2 is correct.

    Correct Answer: B

    Solution :

                     Statement-1: Energy of p" particle from 0 to maximum so \[{{E}_{1}}-{{E}_{2}}\] is the continuous energy spectrum. Statement-2 : For energy conservation and momentum at least three particles daughter nucleus +p-1 and antineutron.


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