• # question_answer Trains are running with speeds 30 km/hr and 58 km/hr in the same direction. A man in the slower train passes the faster train in 18 seconds. The length of faster train is A)  125 m    B)  140 m C)  150 m  D)  160 m

[b] Distance travelled by slower train in 18 sec $=30\times \frac{5}{18}\times 18=150\,m$ Distance travelled by faster train in 18 sec $=58\times \frac{5}{18}\times 18=290\,m$ $\therefore$ The length of faster train = 290 ? 150 = 140m