A) 125 m
B) 140 m
C) 150 m
D) 160 m
Correct Answer: B
Solution :
[b] Distance travelled by slower train in 18 sec \[=30\times \frac{5}{18}\times 18=150\,m\] Distance travelled by faster train in 18 sec \[=58\times \frac{5}{18}\times 18=290\,m\] \[\therefore \] The length of faster train = 290 ? 150 = 140mYou need to login to perform this action.
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