| A particle is displaced from \[x=-6\text{ }m\] to \[x=+6\text{ }m\]. A force F acting on the particle during its motion in shown in figure. Graph between work done by this force (W) and displacement (x) should be |
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A)
B)
C)
D)
Correct Answer: A
Solution :
[a] W = Area under F-X graph. From \[x=-6\text{ }m\]to\[x=0\], force is in negative x-direction and displacement is in positive x-direction. Therefore, work done will be negative and since force is constant, W-x graph will be a straight line. From \[x=0\]to \[x=+3\]m, force is negative and displacement is positive, hence, work done will be negative and W-x graph will be a parabola. From \[x=+3\,m\]to\[x=+6\,m\], force and displacement both are positive, therefore, work done is also positive and W-x graph will be a parabola.
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