JEE Main & Advanced Physics Transmission of Heat Sample Paper Topic Test - Transmission Of Heat

  • question_answer
    Three discs A, B and C having radii 2 m, 4 m and 6 m respectively on coated with carbon black on their outer surfaces. The wavelength corresponding to maximum intensities are 300 nm, 400 nm and 500 nm respectively. The power radiated by them are \[{{Q}_{A}},\,{{Q}_{B}}\] and \[{{Q}_{C}}\] respectively

    A) \[{{Q}_{A}}\] is maximum

    B) \[{{Q}_{B}}\] is maximum

    C) \[{{Q}_{C}}\] is maximum

    D) \[{{Q}_{A}}={{Q}_{B}}={{Q}_{C}}\]

    Correct Answer: B

    Solution :

    [b] Idea The radiant power i.e., energy radiated by a body per unit time is given by \[\frac{Q}{t}=A\varepsilon \sigma {{T}^{4}}\]
    \[\Rightarrow \]   \[Q\propto A{{T}^{4}}\]
                Also \[{{\lambda }_{m}}T=\text{constant}\]
    \[\Rightarrow \]   \[Q\propto \frac{A}{{{({{\lambda }_{m}})}^{4}}}\]
    Power radiated, \[Q\propto A{{T}^{4}}\] and \[{{\lambda }_{m}}T=\] constant
    Hence, \[Q\propto \frac{A}{{{({{\lambda }_{m}})}^{4}}}\] or \[Q\propto \frac{{{r}^{2}}}{{{({{\lambda }_{m}})}^{4}}}\]
    \[{{Q}_{A}}:{{Q}_{B}}:{{Q}_{C}}=\frac{{{(2)}^{2}}}{{{(3)}^{4}}}:\frac{{{(4)}^{2}}}{{{(4)}^{4}}}:\frac{{{(6)}^{2}}}{{{(5)}^{4}}}\]
    \[=0.05:0.0625:0.0576\]
    i.e., \[{{Q}_{B}}\] is maximum.
    TEST Edge Question related to Kirchhoff’s law, Stefan's law, Newton's law of cooling and Wien's displacement law are frequently asked, students are advised, to have better understanding of concept and application of these topics.


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