JEE Main & Advanced Physics Thermometry, Calorimetry & Thermal Expansion Sample Paper Topic Test - Thermometry, Calorimetry & Thermal Expansion

  • question_answer
    A pendulum clock keeps correct time at \[0{}^\circ C\]. Its mean coefficient of linear expansions is a\[{{\alpha }^{o}}{{C}^{-1}}\]. The loss in seconds per day by the clock if the temperature rises by \[t{}^\circ C\] is

    A) \[\frac{\frac{1}{2}\alpha t\times 864000}{1-\frac{\alpha \,t}{2}}\]

    B) \[\frac{1}{2}\alpha \,t\times 86400\]

    C) \[\frac{\frac{1}{2}\alpha \,t\times 86400}{{{\left( 1+\frac{\alpha \,t}{2} \right)}^{2}}}\]  

    D) \[\frac{\frac{1}{2}\alpha \,t\times 86400}{1+\frac{\alpha \,t}{2}}\]

    Correct Answer: B

    Solution :

    T = Time period
    \[T\,\propto \,{{\ell }^{1/2}}\]
    \[\frac{\Delta T}{T}=\frac{1}{2}\frac{\Delta \ell }{\ell }=\frac{1}{2}\alpha t;\]
    \[\Delta T=\frac{1}{2}\alpha tT=\alpha t\]
    Total loss \[=\frac{1}{2}\alpha t\times 86400\]


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