| The following transition occurs when Lithium atoms are sprayed into hot flame. The various steps are numbered for identification. |
| \[2s\xrightarrow{I}2p\xrightarrow{II}3d\xrightarrow{III}3p\xrightarrow{IV}\]\[4s\xrightarrow{V}3p\] |
| Which of these transitions result in emission of light? |
A) I, II & V
B) III & V
C) III, IV & V
D) All
Correct Answer: B
Solution :
[b] \[2s\xrightarrow{I}2p\xrightarrow{II}3d\xrightarrow{III}3p\xrightarrow{IV}4s\xrightarrow{V}3p\] Energy of 3d is more than 3p therefore it will emit energy, similarly from \[4s\to 3p\] transition.
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