A) \[\frac{1}{2}\,\frac{{{J}^{2}}}{m{{r}^{2}}}\]
B) \[\frac{Jv}{r}\]
C) \[\frac{{{J}^{2}}}{2m}\]
D) \[\frac{{{J}^{2}}}{2\,\pi }\]
Correct Answer: A
Solution :
| [a] Angular momentum \[J=mvr\] |
| \[{{J}^{2}}={{m}^{2}}{{v}^{2}}{{r}^{2}}\] |
| or \[\frac{{{J}^{2}}}{2}=\left( \frac{1}{2}m{{v}^{2}} \right)m{{r}^{2}}\] |
| or \[KE=\frac{{{J}^{2}}}{2m{{r}^{2}}}\] |
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