A) 4
B) 15
C) 3
D) 6
Correct Answer: D
Solution :
| [d] \[n=4\ell =0\] \[{{m}_{e}}=0\] |
| \[\ell =2;\,\,\,\,{{m}_{e}}=-1,\,\,\,\,0+1\] |
| \[\ell =2;\,\,\,{{m}_{e}}=-2,\,\,\,-1,\,\,\,0+1,\,\,+2\] |
| \[\ell =3;\,\,\,{{m}_{e}}=-3,\,\,-2,\,\,-1,\,\,0+1,\,\,+2+3\] |
| There are three orbitals having \[{{m}_{e}}=+1\] thus maximum number of electrons in them will be 6. |
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