A) x/6
B) 5x
C) 7.2 x
D) 5x/36
Correct Answer: D
Solution :
[d] \[{{(IE)}_{H}}={{E}_{\infty }}-{{E}_{1}}=-{{E}_{1}}=x\] volt |
Put \[{{E}_{1}}=-\frac{K}{{{n}^{2}}}=-\frac{K}{{{1}^{2}}}=-K\] |
\[\therefore \] \[K=x\] |
\[\Delta E={{E}_{3}}-{{E}_{2}}\] |
\[=-K/{{3}^{2}}-(-K/{{2}^{2}})\] |
\[=K\frac{5}{36}=\frac{5x}{36}\] |
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