A) \[-\frac{1}{3}\]
B) \[-\frac{1}{4}\]
C) + 4
D) + 3
Correct Answer: A
Solution :
| [a] \[K{{I}_{3}},\text{ }1+3\times \left( a \right)=0\] |
| \[a=-\frac{1}{3}\] |
| or \[K{{I}_{3}},\] is \[KI+{{I}_{2}}\] |
| \[\therefore \] I has two oxidation no. - 1 and 0 respectively. |
| However factually speaking oxidation number of I in \[K{{I}_{3}}\] is an average of two values - 1 and 0. |
| \[\text{Average O}\text{.N}\text{.}=\frac{-1+2\times \left( 0 \right)}{3}=-\frac{1}{3}.\] |
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