A) + 6
B) zero
C) + 3
D) + 2
Correct Answer: C
Solution :
| [c] Let the O.N. of Co be x |
| O.N. of \[N{{H}_{3}}\] is zero |
| O.N. of Cl is - 1 |
| O.N. of Br is - 1 |
| \[\therefore \] \[ON\left( Co \right)+6ON\left( N{{H}_{3}} \right)+2ON\left( Cl \right)\]\[+ON\left( Br \right)=0\] |
| \[\Rightarrow \] \[x+6\left( 0 \right)-1\times 2-1=0\] |
| \[\therefore \] \[x=+3\] |
| So, the oxidation number of cobalt in the given complex compound is +3. |
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