A) \[\frac{M}{14}\]
B) \[\frac{M}{28}\]
C) \[\frac{M}{7}\]
D) \[\frac{M}{10}\]
Correct Answer: B
Solution :
| [b] Idea This problem is based on concept of n-factor determination and their equivalent wt. determination. |
| ? Determine the n-factor first |
| ? Then, equivalent wt. \[=\frac{\text{molecular wt}.}{\text{n-factor}}\] |
| Oxidation state of As \[O_{4}^{3-}=x-2\times 4=-3\] |
| \[x-8=-3\] |
| \[x=5\] |
| Oxidation state of S in \[SO_{4}^{2-}=x-2\times 4=-2\] |
| \[x-2+8=+6\] |
| n-factor = Sum of positive oxidation states |
| = Total oxidation state of \[2AsO_{4}^{3-}\] + Total oxidation state of \[SO_{4}^{2-}\] |
| \[=2\times 5+3\times 6=10+18=28\] |
| Equivalent wt. \[=\frac{M}{28}\] |
| TEST Edge Question related to determination of equivalent wt. of different sols, in different medium may also be asked frequently so, students are advised to study equivalent wt. of \[KMn{{O}_{4}}\] in acidic, basic and neutral medium. |
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