A) increases
B) decreases
C) increases and decreases
D) decreases and increases
Correct Answer: A
Solution :
[a] \[x=a{{e}^{-\alpha t}}+b{{e}^{\beta t}}\] \[v=\frac{dx}{ddt}=-\alpha a{{e}^{-\alpha t}}+\beta b{{e}^{\beta t}}\] As t increases, negative value \[\alpha a{{e}^{-\alpha t}}\] decreases. So v increases.
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