A)
B)
C)
D)
Correct Answer: D
Solution :
[d] a-\[{{\overset{\to }{\mathop{F}}\,}_{BAC}}={{\overset{\to }{\mathop{F}}\,}_{BDC}}={{\overset{\to }{\mathop{F}}\,}_{BC}}\] equation can be written as |
\[a={{a}_{0}}-kv\] |
Here \[{{a}_{0}}\] and k are positive constants |
or \[\frac{dv}{dt}={{a}_{0}}-kv\] |
or \[\frac{dv}{{{a}_{0}}-kv}-dt\] |
On integration, we get |
\[v=\frac{{{a}_{0}}}{k}(1-{{e}^{-tk}})\] |
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