| A body of mass 50 kg resting on a smooth inclined plane is connected by a massless inextensible string passing over a smooth pulley, at the top of the inclined plane have another mass of 40 kg as shown in the figure. The distance through which 50 kg mass fall in 4 sec will be - |
| (The angle of the inclined plane is \[{{30}^{o}}\]) |
 |
A) 13.04 m
B) 1.63 m
C) 1.304 m
D) 16.3 m
Correct Answer: A
Solution :
[a]| The tension is same in two segments | |
| For B the equation is | |
| \[(40\times 9.8-T)=40\,a\] | ...(1) |
| For C the equation is | |
| \[(T-50\times 9.8\times \frac{1}{2})=50\,a\] | ...(2) |
| From equation (1) and (2) \[a=1.63\text{ }m/{{s}_{2}}\] distance of fall | |
| \[S=\frac{1}{2}a{{t}^{2}}=\frac{1}{2}\times 1.63\times {{4}^{2}}=13.04\,m\] | |
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