A) \[\overrightarrow{N}+\overrightarrow{T}+\overrightarrow{W}=0\]
B) \[{{T}^{2}}+{{N}^{2}}+{{W}^{2}}=0\]
C) \[T=N+W\]
D) \[N=W\sin \theta \]
Correct Answer: A
Solution :
[a] For equilibrium of sphere, vector sum of all the forces must be zero. Hence \[\overrightarrow{N}+\overrightarrow{T}+\overrightarrow{W}=0\]. Also by componenting, \[T\cos \theta =W\] and \[T\sin \theta =N.\] Hence \[{{T}^{2}}={{W}^{2}}+{{N}^{2}}\] and \[N=W\tan \theta \]
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