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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Ionic Equilibrium

  • question_answer
    10 mL, of a strong acid solution of \[pH=2.000\] are mixed with 990 mL of another strong acid solution of \[pH=4.000\]. The pH of the resulting solution will be:

    A) 4.002

    B) 4.000     

    C)          4.200

    D) 3.7

    Correct Answer: D

    Solution :

    [d] \[[{{H}^{+}}]\] after mixing
    \[=\frac{{{10}^{-2}}\times 10+{{10}^{-4}}\times 990}{1000}\]
    \[\frac{0.1=0.0990}{1000}=\frac{0.1990}{1000}=1.99\times {{10}^{-4}}\]
    \[\therefore \]      \[pH=4-0.3=3.7\]


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