JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Ionic Equilibrium

  • question_answer
    The solubility of \[AgCl\] in water at \[25{}^\circ C\] is \[1.79\times {{10}^{-3}}g/L\]. The \[{{K}_{sp}}\] of \[AgCl\] at \[25{}^\circ C\] is

    A) \[1.68\times {{10}^{-12}}\]

    B) \[1.55\times {{10}^{-10}}\]

    C) \[12.4\times {{10}^{-8}}\]

    D) \[1.73\times {{10}^{-14}}\]

    Correct Answer: B

    Solution :

    [b] Solubility of \[AgCl\] in water
    \[=1.79\times {{10}^{-3}}g/L\]
    \[=\frac{1.79\times {{10}^{-3}}}{143.5}mol/L\]
    \[=1.247\times {{10}^{-5}}mol/L\]
    For        \[AgCl\]
    \[{{K}_{sp}}=S\times S={{S}^{2}}\]
    \[={{(1.247\times {{10}^{-5}})}^{2}}\]
    \[=1.55\times {{10}^{-10}}mo{{l}^{2}}{{L}^{-2}}\]


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