JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Sample Paper Topic Test - Ionic Equilibrium

  • question_answer
    If acetic acid is 1.0% ionised in its decinormal solution, then pH of its seminormal solution will be

    A) 3.4

    B) 4.8    

    C) 1.6

    D) 2.6

    Correct Answer: D

    Solution :

    [d] \[C{{H}_{3}}COOH\,C{{H}_{3}}CO{{O}^{-}}+\,{{H}^{+}}\]
    \[\begin{matrix}    \text{Initial}\,\text{conce}\text{.}\,\,\,\frac{1}{10} & 0 & 0  \\    \text{After}\,t\,\text{time}\,\,\,\,\,\,\frac{1}{10}-\frac{1}{10}\times \frac{1.0}{100} & \frac{1}{10}\times \frac{1.0}{100} & \frac{1}{10}\times \frac{1.0}{100}  \\    \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,=0.1 & \,\,\,\,\,\,\,\,\,\,\,=0.001 & \,\,\,\,\,\,\,\,=0.001  \\ \end{matrix}\]
    \[K=\frac{0.001\times 0.001}{0.1}\]
    \[=1\times {{10}^{-5}}\]                                  …(i)
    In case of seminormal solution
     \[C{{H}_{3}}COOH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}CO{{O}^{-}}\,\,\,\,\,+\,\,\,\,\,\,{{H}^{+}}\]\[\begin{matrix}    \text{Initial}\,\text{conc}\text{.}\,\,\,\,\frac{1}{2} & 0 & 0  \\    \text{After}\,t\,\text{time}\,\,\frac{1}{2}-\frac{1}{2}\times \frac{x}{100} & \,\,\,\frac{1}{2}\times \frac{x}{100}\,\,\, & \frac{1}{2}\times \frac{x}{100}  \\ \end{matrix}\]
        \[=0.5\]       [let solution is \[x%\] ionised]
    \[K=\frac{{{\left( \frac{1}{2}\times \frac{x}{100} \right)}^{2}}}{0.5}\]
    \[=\frac{{{x}^{2}}}{20000}\]              …(ii)
    From Eqs (i) and (ii)
    \[\frac{{{x}^{2}}}{20000}=1\times {{10}^{-5}}\]
    \[x=0.447\]
    \[[{{H}^{+}}]=\frac{1}{2}\times \frac{x}{100}\]
    \[=\frac{1}{2}\times \frac{0.447}{100}=0.00224\]
    \[pH=-\log \,[{{H}^{+}}]\]
     \[=-\log \,[0.00224]=2.65\]


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