| For the gas-phase hydration of hexafluoroacetone : |
| \[(C{{F}_{3}})CO+{{H}_{2}}O{{(C{{F}_{3}})}_{2}}C{{(OH)}_{2}}\] |
| at \[{{76}^{o}}C,{{K}_{f}}=0.13M{{s}^{-1}}\] |
| and \[{{K}_{b}}=6.2\times {{10}^{-4}}M{{s}^{-1}}\] then equilibrium constant \[{{K}_{c}}\] is : |
A) \[4.77\times {{10}^{-3}}\]
B) 209.7
C) \[2.96\times {{10}^{-7}}\]
D) \[3.38\times {{10}^{6}}\]
Correct Answer: B
Solution :
[b] \[K=\frac{{{K}_{t}}}{{{K}_{b}}}=\frac{0.13}{6.2\times {{10}^{-4}}}=209.7\]
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