A) 80%
B) 22%
C) 40%
D) 60%
Correct Answer: A
Solution :
| [a] \[\alpha =\frac{{{V}_{\infty }}-{{V}_{0}}}{(n-1){{V}_{0}}}\] |
| \[=\frac{104.25-57.9}{(2-1)\times 57.9}=0.80\] |
| \[{{V}_{\infty }}=\frac{208.5}{2}\](\[\because {{V}_{0}}\times 2=\]molar mass) |
| Hence, degree of dissociation = 80% |
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