A) 4
B) 16
C) \[\frac{1}{4}\]
D) \[\frac{1}{16}\]
Correct Answer: D
Solution :
[d] \[\sqrt[3]{{{\left( \frac{1}{64} \right)}^{2}}}={{\left[ {{\left( \frac{1}{64} \right)}^{2}} \right]}^{\frac{1}{3}}}={{\left( \frac{1}{64} \right)}^{\frac{2}{3}}}\] \[{{\left( \frac{1}{4} \right)}^{3\times \frac{2}{3}}}={{\left( \frac{1}{4} \right)}^{2}}=\frac{1}{16}\]You need to login to perform this action.
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