A) \[n\]
B) \[\frac{n-1}{2}\]
C) \[\frac{n+1}{2}\]
D) \[\frac{n}{2}\]
Correct Answer: C
Solution :
[c] \[\left( 1+\frac{1}{2} \right)\left( 1+\frac{1}{3} \right)\left( 1+\frac{1}{4} \right).....\left( 1+\frac{1}{n} \right)\] \[\frac{3}{2}\times \frac{4}{3}\times \frac{5}{4}\times ....\times \frac{n+1}{n}\] \[=\frac{n+1}{2}\]
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