A) 991
B) 9
C) 1000
D) \[991\times 9\]
Correct Answer: C
Solution :
[c] \[\frac{{{(991)}^{3}}+{{(9)}^{3}}}{{{(991)}^{2}}-991\times 9+{{(9)}^{2}}}\] As \[\frac{{{a}^{3}}+{{b}^{3}}}{{{a}^{2}}-ab+{{b}^{2}}}=\frac{\left( a+b \right)\left( {{a}^{2}}-ab+{{b}^{2}} \right)}{\left( {{a}^{2}}-ab+{{b}^{2}} \right)}\] = a + b \[\therefore \] \[991+9=1000\]You need to login to perform this action.
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