A) 7
B) 6
C) 5
D) 4
Correct Answer: D
Solution :
When the money becomes double \[2x=x{{\left( 1+\frac{20}{100} \right)}^{n}}2={{\left( \frac{120}{100} \right)}^{n}};\,2={{\left( \frac{6}{5} \right)}^{n}}\] for \[n=1;\,\,2>\frac{6}{5}\Rightarrow \] for \[n=2;\,2>\frac{36}{25}\] for \[n=4;2<\frac{1296}{625}\] \[\therefore \] Least number of years \[=\]
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