A) 2 min 24 sec.
B) 3 min 12 sec.
C) 4 min.
D) None of these.
Correct Answer: A
Solution :
[a] Let the side of square field = ?a? m \[\therefore \,\] Area of square field \[{{a}^{2}}\,\,sq.m\] \[{{a}^{2}}=22500\,\,{{m}^{2}}\] \[\Rightarrow \] \[a=150\,\,m\] Speed of cycling = 15 km / hr. \[=\frac{15\times 1000}{60\times 60}=\frac{25}{6}m/s.\] Now, total distance to be covered along the boundary \[=4\times 150=600\,\,m\] \[\because \,\,\frac{25}{6}m\] is covered in 1 sec. \[\therefore \,\]600 m is covered in \[\frac{600}{25}\times 6=144\,\sec \] \[=2\,\,\min \,\,24\,\,\sec .\]
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