A) 6, 9, 12
B) 4, 6, 8
C) 12, 18, 24
D) 14, 21, 28
Correct Answer: D
Solution :
[d] Let the ratio numbers be x. \[\therefore \] Numbers are 2x, 3x, & 4x. \[\therefore \] \[{{(2x)}^{3}}+{{(3x)}^{3}}+{{(4x)}^{3}}=33957\] \[\Rightarrow \] \[8{{x}^{3}}+27{{x}^{3}}+64{{x}^{3}}=33957\] \[\Rightarrow \] \[99{{x}^{3}}=33957\] \[\Rightarrow \] \[{{x}^{3}}=\frac{33957}{99}\] \[\Rightarrow \] \[{{x}^{3}}=343\Rightarrow x=7\] \[\therefore \] Numbers are \[2\times 7,\,\,3\times 7,\,\,4\times 7\] i.e. 14, 21, 28
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