Answer:
Given Two triangles and such that
To prove
Construction Draw and
(1/2)
Proof Since, similar triangles are equiangular and their corresponding sides are proportional. Therefore,
and ?(i)(1)
Thus, in and
[each 90°]
[from Eq. (i)]
By AA similarity,
?(ii)(1)
From Eqs. (i) and (ii), we get
?(ii)
Now,
(1/2)
[Area of triangle Base Altitude]
[FromEq. (ii)] (1/2)
?(iii)
But
[by similarity of and]
?(iv)(1/2)
From Eqs. (iii) and (iv), we get
Hence proved.
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