A) \[\frac{4}{9}\]
B) 1
C) 2
D) \[\frac{5}{9}\]
Correct Answer: B
Solution :
\[\frac{b}{a}=0.25\Rightarrow \frac{b}{a}=\frac{1}{4},b=1,a=4\] \[\therefore \] \[\frac{2a-b}{2a+b}+\frac{2}{9}=\frac{2\times 4-1}{2\times 4+1}+\frac{2}{9}\] \[=\frac{7}{9}+\frac{2}{9}=\frac{9}{9}=1\]You need to login to perform this action.
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