Railways Sample Paper RRBs Assistant Loco Pilot and Technician CBT STAGE-I Sample Paper-9

  • question_answer
    \[6\frac{2}{3}+15\frac{1}{4}+3\frac{3}{4}-7\frac{2}{5}\]is equal to

    A)  \[17\frac{4}{15}\]

    B)         \[19\frac{2}{15}\]

    C)  \[18\frac{7}{15}\]        

    D)  \[18\frac{4}{15}\]

    Correct Answer: D

    Solution :

    \[6\frac{2}{3}+15\frac{1}{4}+3\frac{3}{4}-7\frac{2}{5}\] \[\,=6+\frac{2}{3}+15+\frac{1}{4}+3+\frac{3}{4}-7-\frac{2}{5}\] \[=(6+15+3-7)+\left[ \frac{2}{3}+\frac{1}{4}+\frac{3}{4}-\frac{2}{5} \right]\] \[=17+\left[ \frac{2}{3}+1-\frac{2}{5} \right]\] \[\,=17+\left[ \frac{10+15-6}{15} \right]\] \[=17+\frac{19}{15}=17+1+\frac{4}{15}=18\frac{4}{15}\]


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