A) \[y(x+y)\]
B) \[x(x-y)\]
C) \[\frac{xy}{x-y}\]
D) \[\frac{x+y}{x-y}\]
Correct Answer: B
Solution :
Let mean proportional =M \[\therefore \] \[(x-y):M::M({{x}^{3}}-{{x}^{2}}y)\] \[\Rightarrow \] \[{{M}^{2}}=(x-y)\times ({{x}^{3}}-{{x}^{2}}y)\] \[=(x-y)\times {{x}^{2}}\times (x-y)\] \[\,={{x}^{2}}\times {{(x-y)}^{2}}\] \[\therefore \] \[M=x\,\times \,(x-y)\]You need to login to perform this action.
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