A) Rs. 8123.50
B) Rs. 1213.50
C) Rs. 9512.50
D) Rs. 1000.50
Correct Answer: C
Solution :
Let sum received by younger brother = Rs. x \[\therefore \] Sum received by elder brother = Rs.\[(20000-x)\] Given, \[x{{\left[ 1+\frac{5}{100} \right]}^{5}}=(20000-x){{\left[ 1+\frac{5}{100} \right]}^{3}}\] \[\Rightarrow \] \[x{{\left[ 1+\frac{5}{100} \right]}^{2}}=(20000-x)\] \[\Rightarrow \] \[\frac{441x}{400}=20000-x\] \[\Rightarrow \] \[441x+400x=8000000\] \[\therefore \] \[x=\frac{8000000}{841}=\]Rs. 9512. 50You need to login to perform this action.
You will be redirected in
3 sec