| In this question some of the letters are missing which are given in that order as come of the alternative below. |
| \[c\_baa\_aca\_cacab\_acac\_bca\] |
A) acbaa
B) bbcaa
C) bccab
D) cbaac
Correct Answer: A
Solution :
Series \[c\underline{a}b/aa/\underline{c}aca\underline{b}/cacab/\underline{a}a/cac\underline{a}b/ca\] \[\Rightarrow \]\[acbaa\]
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