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Railways Sample Paper RRBs Assistant Loco Pilot and Technician CBT STAGE-I Sample Paper-32

  • question_answer
    The sum of all the 3 digit numbers, each of which on division by 5 leaves remainder 3, is

    A)  180                 

    B)  1550

    C)  6995               

    D)  99090

    Correct Answer: D

    Solution :

    According to the question. First number =a = 103 Last number = I = 998 \[\therefore \]If the number of such numbers be, then \[998=103+(n-1)\times 5\] \[\Rightarrow \]\[(n-1)\times 5=998-103=895\] \[\Rightarrow \]   \[n-1=\frac{895}{5}=179\] \[\Rightarrow \]   \[n=180\] \[\therefore \]      \[S=\frac{n}{2}(a+I)=\frac{180}{2}(103+998)\] \[=90\times 1101=99090\]


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