Railways Sample Paper RRBs Assistant Loco Pilot and Technician CBT STAGE-I Sample Paper-32

  • question_answer
    If 5 tan 6 = 4, then the value of\[\left( \frac{5\sin \theta -3cos\theta }{5\sin \theta +3\cos \theta } \right)\]is

    A)  \[\frac{1}{7}\]             

    B)  \[\frac{2}{7}\]

    C)  \[\frac{5}{7}\]             

    D)  \[\frac{2}{5}\]

    Correct Answer: A

    Solution :

    \[5\tan \theta =4\Rightarrow \tan \theta \frac{4}{5}\] \[\therefore \]\[\frac{5\sin \theta -3\cos \theta }{5\sin \theta +3\cos \theta }=\frac{\frac{5\sin \theta -3\cos \theta }{\cos \theta }}{\frac{5\sin \theta +3\cos \theta }{\cos \theta }}\] \[=\frac{5\tan \theta -3}{5\tan \theta +3}=\frac{5\times \frac{4}{5}-3}{5\times \frac{4}{5}+3}=\frac{4-3}{4+3}=\frac{1}{7}\]


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