A) Rs. 100000
B) Rs. 110000
C) Rs. 120000
D) Rs. 170000
Correct Answer: C
Solution :
Let the sum be Rs. x. Then, SI = Rs.\[\left( x\times \frac{8}{100}\times 2 \right)=\]Rs. \[\frac{4x}{25}\] CI = Rs. \[\left[ x\times {{\left( 1+\frac{8}{100} \right)}^{2}}-x \right]\] = Rs. \[\left[ x\frac{27}{25}\times \frac{27}{25}-x \right]=\]Rs. \[\frac{104}{625}\] \[(CI)-(SI)=\text{Rs}.\,\,\left( \frac{104x}{625}-\frac{4x}{25} \right)=\]Rs. \[\frac{4x}{625}\] \[\therefore \]\[\frac{4x}{625}=768\Rightarrow x=\left( \frac{768\times 625}{4} \right)=120000\] \[\therefore \] Sum = Rs. 120000
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