A) \[\frac{1}{4}\]
B) \[\frac{1}{6}\]
C) \[\frac{2}{3}\]
D) \[\frac{1}{7}\]
Correct Answer: D
Solution :
\[2x+\frac{1}{3x}=5\] \[\Rightarrow \] \[6{{x}^{2}}+1=15x\] \[\Rightarrow \] \[6{{x}^{2}}+20x+1=15x+20x\] = 35x (Adding 20x both sides) \[\therefore \]\[\frac{5x}{6{{x}^{2}}+20x+1}=\frac{5x}{35x}=\frac{1}{7}\]
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