A) \[\frac{1}{9}\]
B) \[\frac{1}{3}\]
C) 3
D) 9
Correct Answer: D
Solution :
Given \[\cot \theta =\frac{4}{3}\] Now,\[\frac{5\sin \theta +3\cos \theta }{5\sin \theta -3\cos \theta }=\frac{5+3\cot \theta }{5-3\cot \theta }\] [on dividing Nr and Dr by \[\cos \theta \]] \[=\frac{5+3\times \frac{4}{3}}{5-3\frac{4}{3}}=\frac{5+4}{5-4}=\frac{9}{1}=9\]
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